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Arbejdsark: Rette linjer

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Rette linjer
Niveau 3 · Linjens ligning
Find ligningen for linjen gennem de to punkter. Skriv den på formen y = kx + m.
1.
(−2, 8)(−1, 5)(-2,\,8) \qquad (-1,\,5)
y=y =
2.
(−2, −1)(−1, 4)(-2,\,-1) \qquad (-1,\,4)
y=y =
3.
(−1, 6)(2, 15)(-1,\,6) \qquad (2,\,15)
y=y =
4.
(−1, 8)(0, 4)(-1,\,8) \qquad (0,\,4)
y=y =
5.
(2, −2)(5, 7)(2,\,-2) \qquad (5,\,7)
y=y =
6.
(−2, −17)(0, −7)(-2,\,-17) \qquad (0,\,-7)
y=y =
7.
(−2, 10)(1, 7)(-2,\,10) \qquad (1,\,7)
y=y =
8.
(−3, −12)(−2, −10)(-3,\,-12) \qquad (-2,\,-10)
y=y =
9.
(−2, 16)(0, 6)(-2,\,16) \qquad (0,\,6)
y=y =
10.
(−2, −7)(4, −10)(-2,\,-7) \qquad (4,\,-10)
y=y =
Facitliste
Rette linjer · Niveau 3 · Linjens ligning
1.y=−3x+2y = -3x + 2
2.y=5x+9y = 5x + 9
3.y=3x+9y = 3x + 9
4.y=−4x+4y = -4x + 4
5.y=3x−8y = 3x - 8
6.y=5x−7y = 5x - 7
7.y=−x+8y = -x + 8
8.y=2x−6y = 2x - 6
9.y=−5x+6y = -5x + 6
10.y=−12x−8y = -\frac{1}{2}x - 8