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Arbejdsark: Brøker

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Brøker
Niveau 2 · Forskellige nævnere
Udregn. Forkort svaret mest muligt.
1.
611+23=‾\frac{6}{11} + \frac{2}{3} = \underline{\hspace{4.5em}}
2.
89−13=‾\frac{8}{9} - \frac{1}{3} = \underline{\hspace{4.5em}}
3.
34−29=‾\frac{3}{4} - \frac{2}{9} = \underline{\hspace{4.5em}}
4.
45−17=‾\frac{4}{5} - \frac{1}{7} = \underline{\hspace{4.5em}}
5.
27−211=‾\frac{2}{7} - \frac{2}{11} = \underline{\hspace{4.5em}}
6.
45+12=‾\frac{4}{5} + \frac{1}{2} = \underline{\hspace{4.5em}}
7.
47−12=‾\frac{4}{7} - \frac{1}{2} = \underline{\hspace{4.5em}}
8.
710−611=‾\frac{7}{10} - \frac{6}{11} = \underline{\hspace{4.5em}}
9.
2−16=‾2 - \frac{1}{6} = \underline{\hspace{4.5em}}
10.
2−58=‾2 - \frac{5}{8} = \underline{\hspace{4.5em}}
Facitliste
Brøker · Niveau 2 · Forskellige nævnere
1.4033=1733\frac{40}{33} = 1\tfrac{7}{33}
2.59\frac{5}{9}
3.1936\frac{19}{36}
4.2335\frac{23}{35}
5.877\frac{8}{77}
6.1310=1310\frac{13}{10} = 1\tfrac{3}{10}
7.114\frac{1}{14}
8.17110\frac{17}{110}
9.116=156\frac{11}{6} = 1\tfrac{5}{6}
10.118=138\frac{11}{8} = 1\tfrac{3}{8}